Parts of Transformer - Electrical Diary

Top 10 Trigonometry Question For the student of 10th Class.The most asked question in various exams up to secondary and higher secondary exams.aTop 10 Trigonometry Question Prove The Following (1)cosx

1+sinx +cosx

1-sinx=2Secx (2)1+Cosx

1-Cosx=Cosecx+Cotx (3)tanx

Secx-1+tanx

Secx+1=2Cosecx (4)tanx

1-cotx+Cotx

1-tanx=1+Secx.Cosecx (5)1

1-Sinx-1

1+Sinx=2Secx.tanx (6)Cosx

1+Sinx+1+Sinx

Cosx=2Secx (7)1+tan2x

1+Cot2 (1-tanx

1-Cotx)2 (8)1+Sinx

Cosx+Cosx

1+Sinx=2Secx (9)1+2tan2x

Cos2x=tan4x+Sec4x (10)(1-Sinx-Cosx)2=2(1-Sinx)(1-Cox)$$\begin{array}{c}\frac{cosx}{1+sinx}+\frac{cosx}{1-sinx}=2Secx\\ \\ \sqrt{\frac{1+Cosx}{1-Cosx}}=Cosecx+Cotx\\ \\ \frac{tanx}{Secx-1}+\frac{tanx}{Secx+1}=2Cosecx\\ \\ \frac{tanx}{1-cotx}+\frac{Cotx}{1-tanx}=1+Secx.Cosecx\\ \\ \frac{1}{1-Sinx}-\frac{1}{1+Sinx}=2Secx.tanx\\ \\ \frac{Cosx}{1+Sinx}+\frac{1+Sinx}{Cosx}=2Secx\\ \\ \frac{1+ta{n}^{2}x}{1+Co{t}^2}(\frac{1-ta{n}^{}x}{1-Cotx}{)}^2\\ \\ \frac{1+Sinx}{Cosx}+\frac{Cosx}{1+Sinx}=2Secx\\ \\ 1+\frac{2ta{n}^2{x}^{}}{Co{s}^{2}x}=ta{n}^{4}x+Se{c}^{4}x\\ \\ (1-Sinx-Cosx{)}^2=\sqrt{2(1-Sinx)(1-Cox)}\end{array}$$ For more Question of Mathematics and other Subject Please Visit https://www.electricaldiary.com