A 4.0 mm-diameter copper ball is charged to 90 nC. What is the number of electrons removed from the Copper ball?

Posted by: Pintu Prasad September 02, 2021

A 4.0 mm-diameter copper ball is charged to 90 nC. What is the number of electrons removed from the Copper ball?

Solution:

Given that

Diameter of Copper Ball = d = 4.00mm

Charge on Ball = q = 90 nC = 90 x 10^-9 C

Charge on an Electron = e =1.6 x 10^-19 C

if N is number of electrons removed from the Copper Ball

$N = Given Charge Charge on electron$

$90 x 10-9+19 90 x 10-9 N= 1,6 X 10-19 = 1.6$

$N= 90 x 10-9+19 90 x 1010 1.6 56.25 x 1010 1.6$

$N = 56,25 x 1010$

this is number of electron remove from Copper

Electrical Diary